Optimal. Leaf size=120 \[ \frac{(e x)^{m+1} (b c-a d) (B c-A d) \, _2F_1\left (1,\frac{m+1}{2};\frac{m+3}{2};-\frac{d x^2}{c}\right )}{c d^2 e (m+1)}-\frac{(e x)^{m+1} (-a B d-A b d+b B c)}{d^2 e (m+1)}+\frac{b B (e x)^{m+3}}{d e^3 (m+3)} \]
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Rubi [A] time = 0.0956785, antiderivative size = 120, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.069, Rules used = {570, 364} \[ \frac{(e x)^{m+1} (b c-a d) (B c-A d) \, _2F_1\left (1,\frac{m+1}{2};\frac{m+3}{2};-\frac{d x^2}{c}\right )}{c d^2 e (m+1)}-\frac{(e x)^{m+1} (-a B d-A b d+b B c)}{d^2 e (m+1)}+\frac{b B (e x)^{m+3}}{d e^3 (m+3)} \]
Antiderivative was successfully verified.
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Rule 570
Rule 364
Rubi steps
\begin{align*} \int \frac{(e x)^m \left (a+b x^2\right ) \left (A+B x^2\right )}{c+d x^2} \, dx &=\int \left (-\frac{(b B c-A b d-a B d) (e x)^m}{d^2}+\frac{b B (e x)^{2+m}}{d e^2}+\frac{\left (b B c^2-A b c d-a B c d+a A d^2\right ) (e x)^m}{d^2 \left (c+d x^2\right )}\right ) \, dx\\ &=-\frac{(b B c-A b d-a B d) (e x)^{1+m}}{d^2 e (1+m)}+\frac{b B (e x)^{3+m}}{d e^3 (3+m)}+\frac{((b c-a d) (B c-A d)) \int \frac{(e x)^m}{c+d x^2} \, dx}{d^2}\\ &=-\frac{(b B c-A b d-a B d) (e x)^{1+m}}{d^2 e (1+m)}+\frac{b B (e x)^{3+m}}{d e^3 (3+m)}+\frac{(b c-a d) (B c-A d) (e x)^{1+m} \, _2F_1\left (1,\frac{1+m}{2};\frac{3+m}{2};-\frac{d x^2}{c}\right )}{c d^2 e (1+m)}\\ \end{align*}
Mathematica [A] time = 0.0988264, size = 93, normalized size = 0.78 \[ \frac{x (e x)^m \left (\frac{(b c-a d) (B c-A d) \, _2F_1\left (1,\frac{m+1}{2};\frac{m+3}{2};-\frac{d x^2}{c}\right )}{c (m+1)}+\frac{a B d+A b d-b B c}{m+1}+\frac{b B d x^2}{m+3}\right )}{d^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.036, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( B{x}^{2}+A \right ) \left ( b{x}^{2}+a \right ) \left ( ex \right ) ^{m}}{d{x}^{2}+c}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x^{2} + A\right )}{\left (b x^{2} + a\right )} \left (e x\right )^{m}}{d x^{2} + c}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B b x^{4} +{\left (B a + A b\right )} x^{2} + A a\right )} \left (e x\right )^{m}}{d x^{2} + c}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 12.9003, size = 428, normalized size = 3.57 \begin{align*} \frac{A a e^{m} m x x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{1}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{1}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )} + \frac{A a e^{m} x x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{1}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{1}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )} + \frac{A b e^{m} m x^{3} x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{3}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{5}{2}\right )} + \frac{3 A b e^{m} x^{3} x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{3}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{5}{2}\right )} + \frac{B a e^{m} m x^{3} x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{3}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{5}{2}\right )} + \frac{3 B a e^{m} x^{3} x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{3}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{5}{2}\right )} + \frac{B b e^{m} m x^{5} x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{5}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{5}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{7}{2}\right )} + \frac{5 B b e^{m} x^{5} x^{m} \Phi \left (\frac{d x^{2} e^{i \pi }}{c}, 1, \frac{m}{2} + \frac{5}{2}\right ) \Gamma \left (\frac{m}{2} + \frac{5}{2}\right )}{4 c \Gamma \left (\frac{m}{2} + \frac{7}{2}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x^{2} + A\right )}{\left (b x^{2} + a\right )} \left (e x\right )^{m}}{d x^{2} + c}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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